by Chris Peterson » Mon Jul 19, 2021 11:42 pm
neufer wrote: ↑Mon Jul 19, 2021 11:10 pm
http://www.ianmorison.com/rich-field-telescopes-and-wide-field-observing/ wrote:
Professor Morison's Astronomy Digest
Rich Field Telescopes and Wide Field Observing
<<As the name implies, a Rich Field Telescope is one that will show the observer the maximum possible number of stars within the field of view when looking, say, towards the Milky Way. Using such a telescope to sweep along the Milky Way on a dark moonless night, is one of the most beautiful sights that can be seen in the heavens.
It turns out that we tend to see the most stars when the exit pupil of the telescope/eyepiece combination equals that of the dark adapted eye. In young people this is approximately 7 mm but, sadly, as we age this slowly drops down towards 5 or 5.5 mm. The exit pupil is the telescope aperture divided by the magnification. Let us use a mid-range exit pupil diameter of 6 mm and calculate the appropriate magnifications for a range of telescopes. For a 70 mm aperture one would need a magnification of 11.6, for an 80 mm refractor x13.3, a 102mm (4 inch) telescope x17, a 150mm telescope x25, a 200 mm (8 inch) x33.3 and a 300 mm (12 inch) x50.>>
- 1) At lower magnification than the Goldilocks/optimal faint object magnification (= aperture/6mm) all the light collected by the telescope aperture does not make it into the pupil such tbat one cannot see the faintest/most distant stars.
2) At higher magnification than the Goldilocks/optimal faint object magnification (= aperture/6mm) the faintest/most distant stars are all visible; however, they are now spread out such that fewer are in one's field of view (so that the average star field is fainter). Similarly, other resolved continuous fields like large gaseous nebula will also appear fainter.
The ideal magnification for small gaseous nebula is discussed by alter-ego:
http://asterisk.apod.com/viewtopic.php? ... 83#p314983
An interesting consequence of this, and an interesting thought problem, is to consider why we don't blind ourselves when looking at the Moon with a large aperture. In particular, consider a telescope with, say, a 1 meter aperture and an eyepiece chosen to produce a magnification of one (e.g. a 5 m focal length EP on a telescope with a 5 m focal length). On first thought, we might consider that this would introduce more light to the eye by the ratio of the squares of the telescope aperture to the pupil diameter. So, 1000mm^2 / 6mm^2 = 28 thousand. That seems like it would be enough brighter to do some damage. But the formula you give for the exit aperture works both ways. If your telescope has a magnification of one, the entrance pupil of your eye maps to the entrance aperture of the telescope. Doesn't matter if it's a meter in diameter, only light entering the central 7mm makes it into your eye. So the image through this telescope is exactly what you'd see without the telescope (except for some reduction due to losses in the system).
You could light a piece of paper on fire using the Moon and a large enough mirror... but in that case the optical system isn't a telescope, it's just a single objective.
[quote=neufer post_id=315137 time=1626736232 user_id=124483]
[quote=http://www.ianmorison.com/rich-field-telescopes-and-wide-field-observing/]
[c][size=135]Professor Morison's Astronomy Digest
Rich Field Telescopes and Wide Field Observing[/size][/c]
<<As the name implies, a Rich Field Telescope is one that will show the observer the maximum possible number of stars within the field of view when looking, say, towards the Milky Way. Using such a telescope to sweep along the Milky Way on a dark moonless night, is one of the most beautiful sights that can be seen in the heavens.
It turns out that we tend to see the most stars when the exit pupil of the telescope/eyepiece combination equals that of the dark adapted eye. In young people this is approximately 7 mm but, sadly, as we age this slowly drops down towards 5 or 5.5 mm. The exit pupil is the telescope aperture divided by the magnification. Let us use a mid-range exit pupil diameter of 6 mm and calculate the appropriate magnifications for a range of telescopes. For a 70 mm aperture one would need a magnification of 11.6, for an 80 mm refractor x13.3, a 102mm (4 inch) telescope x17, a 150mm telescope x25, a 200 mm (8 inch) x33.3 and a 300 mm (12 inch) x50.>>[/quote]
[b][list]1) [color=#0000FF]At [u]lower[/u] magnification than the [b][color=#0000FF]Goldilocks/optimal faint object magnification (= aperture/6mm)[/color][/b] all the light collected by the telescope aperture [u]does not make it into the pupil[/u] such tbat one cannot see the faintest/most distant stars.[/color][/b]
[img3=Schematic of Keplerian refracting telescope.]https://upload.wikimedia.org/wikipedia/commons/2/26/Kepschem.png[/img3]
[b]2) At [u]higher[/u] magnification than the [b][color=#0000FF]Goldilocks/optimal faint object magnification (= aperture/6mm)[/color][/b] the faintest/most distant stars are all visible; however, [u]they are now spread out such that fewer are in one's field of view[/u] (so that the average star field is fainter). Similarly, other [u]resolved[/u] continuous fields like [u]large[/u] gaseous nebula will also appear fainter.
The ideal magnification for [u]small[/u] gaseous nebula is discussed by alter-ego:
http://asterisk.apod.com/viewtopic.php?f=9&t=41797&p=314983#p314983[/b][/list]
[/quote]
An interesting consequence of this, and an interesting thought problem, is to consider why we don't blind ourselves when looking at the Moon with a large aperture. In particular, consider a telescope with, say, a 1 meter aperture and an eyepiece chosen to produce a magnification of one (e.g. a 5 m focal length EP on a telescope with a 5 m focal length). On first thought, we might consider that this would introduce more light to the eye by the ratio of the squares of the telescope aperture to the pupil diameter. So, 1000mm^2 / 6mm^2 = 28 thousand. That seems like it would be enough brighter to do some damage. But the formula you give for the exit aperture works both ways. If your telescope has a magnification of one, the entrance pupil of your eye maps to the entrance aperture of the telescope. Doesn't matter if it's a meter in diameter, only light entering the central 7mm makes it into your eye. So the image through this telescope is exactly what you'd see without the telescope (except for some reduction due to losses in the system).
You could light a piece of paper on fire using the Moon and a large enough mirror... but in that case the optical system isn't a telescope, it's just a single objective.