Bruce i have 2.97E-8 m/s2 for the sun acceleration and 5.95E-9 m/s2 for the black hole acceleration at t0.
I slice the 150E14 meter distance at t0 (1000 AU).(Number of slice= 42800 ) As the 2 mass get closer, the distance each slice have is diminish because the gravity force is getting stronger. Did it untill the 2 mass are at 7E8 meter distance. Wich is the surface of the sun( i suppose). Then i did continue after that untill the balck hole is a third inside the sun. just to see how much speed it add up.
For each distance, excel recalculate the Force, the Acceleration and the Speed. i use the new final speed of that calcul and add it to the one before to estimate the time it took for the next slice of distance to be cross. i also add the speed of the sun for each slice to the BH speed wich include the initial speed of 4E6 m/s. With that new time for crossing the next slice excel repeat all calculs.
PS: (The post before, i calculate the acceleration with the 2 mass body. Now i calculate the sun and the black hole acceleration separately and take them together as i go down in each distance.) Thanks for reminding me to do so.
So, at sun surface i get 4276 km/s.
A third Inside the sun i get 4422 km/s. Using the time to get a third Inside the sun ( as if acceleration continue) and the rest distance being cross at 4422 km/s i got 5 minutes and 19 seconde to cross it.
At the sun surface speed of 4276 km/s it take 5 minutes 27 secondes to cross the sun. Not much difference.
Question:
If the sun (G0 star) survive that encounter, will it become a k9 or k8 star or smaller? I wont try to calculate that
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