Stickler wrote:With the difference in mass between each object, the difference between the feather and the ball is grossly insignificant. If you were to measure the difference between a five-pound ball and a 50,000-pound ball in the gravitational attraction to the moon, I suspect you would see a difference. The same is true on earth - if one selected objects of a significant difference, relative to the mass of the earth, the gravitational force would effect an increase in attractive force.
Actually, this isn't true. It does not matter if a five-pound ball and a ten-ton ball are dropped at the same time, they are still going to hit the ground at the same time, because objects fall at a rate of 9.4 meters faster every second. However, having a lot
more mass than the five-pound ball, the ten-ton ball will hit the ground with a lot
Yoshi wrote:I clocked the time between the release and the hit and came up with 0.7-0.8 seconds. assuming it dropped from ~0.8 m, the acceleration of gravity calculates to 2-3 m/s2, which is much larger than 1.63 by wikipedia.
First of all, you have to figure out the exact distance from his dropping point to the ground. It is rather hard to just estimate instead of using proportions. Next, you have to figure out how much less gravity is on the moon than on earth. Now, use the rate of 9.8 meters to figure out how long it takes for these objects to touch the ground. However, you have to divide 9.8 by the amount of gravity on the moon to have an answer of how fast the objects fall using that rate. Like I said before, the objects fall at the same speed, but the hammer has a greater force upon hitting the ground.